Integrand size = 18, antiderivative size = 537 \[ \int x^2 \cos \left (a+b \sqrt [3]{c+d x}\right ) \, dx=-\frac {720 c \cos \left (a+b \sqrt [3]{c+d x}\right )}{b^6 d^3}-\frac {120960 \sqrt [3]{c+d x} \cos \left (a+b \sqrt [3]{c+d x}\right )}{b^8 d^3}+\frac {6 c^2 \sqrt [3]{c+d x} \cos \left (a+b \sqrt [3]{c+d x}\right )}{b^2 d^3}+\frac {360 c (c+d x)^{2/3} \cos \left (a+b \sqrt [3]{c+d x}\right )}{b^4 d^3}+\frac {20160 (c+d x) \cos \left (a+b \sqrt [3]{c+d x}\right )}{b^6 d^3}-\frac {30 c (c+d x)^{4/3} \cos \left (a+b \sqrt [3]{c+d x}\right )}{b^2 d^3}-\frac {1008 (c+d x)^{5/3} \cos \left (a+b \sqrt [3]{c+d x}\right )}{b^4 d^3}+\frac {24 (c+d x)^{7/3} \cos \left (a+b \sqrt [3]{c+d x}\right )}{b^2 d^3}+\frac {120960 \sin \left (a+b \sqrt [3]{c+d x}\right )}{b^9 d^3}-\frac {6 c^2 \sin \left (a+b \sqrt [3]{c+d x}\right )}{b^3 d^3}-\frac {720 c \sqrt [3]{c+d x} \sin \left (a+b \sqrt [3]{c+d x}\right )}{b^5 d^3}-\frac {60480 (c+d x)^{2/3} \sin \left (a+b \sqrt [3]{c+d x}\right )}{b^7 d^3}+\frac {3 c^2 (c+d x)^{2/3} \sin \left (a+b \sqrt [3]{c+d x}\right )}{b d^3}+\frac {120 c (c+d x) \sin \left (a+b \sqrt [3]{c+d x}\right )}{b^3 d^3}+\frac {5040 (c+d x)^{4/3} \sin \left (a+b \sqrt [3]{c+d x}\right )}{b^5 d^3}-\frac {6 c (c+d x)^{5/3} \sin \left (a+b \sqrt [3]{c+d x}\right )}{b d^3}-\frac {168 (c+d x)^2 \sin \left (a+b \sqrt [3]{c+d x}\right )}{b^3 d^3}+\frac {3 (c+d x)^{8/3} \sin \left (a+b \sqrt [3]{c+d x}\right )}{b d^3} \]
-720*c*cos(a+b*(d*x+c)^(1/3))/b^6/d^3-120960*(d*x+c)^(1/3)*cos(a+b*(d*x+c) ^(1/3))/b^8/d^3+6*c^2*(d*x+c)^(1/3)*cos(a+b*(d*x+c)^(1/3))/b^2/d^3+360*c*( d*x+c)^(2/3)*cos(a+b*(d*x+c)^(1/3))/b^4/d^3+20160*(d*x+c)*cos(a+b*(d*x+c)^ (1/3))/b^6/d^3-30*c*(d*x+c)^(4/3)*cos(a+b*(d*x+c)^(1/3))/b^2/d^3-1008*(d*x +c)^(5/3)*cos(a+b*(d*x+c)^(1/3))/b^4/d^3+24*(d*x+c)^(7/3)*cos(a+b*(d*x+c)^ (1/3))/b^2/d^3+120960*sin(a+b*(d*x+c)^(1/3))/b^9/d^3-6*c^2*sin(a+b*(d*x+c) ^(1/3))/b^3/d^3-720*c*(d*x+c)^(1/3)*sin(a+b*(d*x+c)^(1/3))/b^5/d^3-60480*( d*x+c)^(2/3)*sin(a+b*(d*x+c)^(1/3))/b^7/d^3+3*c^2*(d*x+c)^(2/3)*sin(a+b*(d *x+c)^(1/3))/b/d^3+120*c*(d*x+c)*sin(a+b*(d*x+c)^(1/3))/b^3/d^3+5040*(d*x+ c)^(4/3)*sin(a+b*(d*x+c)^(1/3))/b^5/d^3-6*c*(d*x+c)^(5/3)*sin(a+b*(d*x+c)^ (1/3))/b/d^3-168*(d*x+c)^2*sin(a+b*(d*x+c)^(1/3))/b^3/d^3+3*(d*x+c)^(8/3)* sin(a+b*(d*x+c)^(1/3))/b/d^3
Result contains complex when optimal does not.
Time = 1.21 (sec) , antiderivative size = 382, normalized size of antiderivative = 0.71 \[ \int x^2 \cos \left (a+b \sqrt [3]{c+d x}\right ) \, dx=\frac {3 e^{-i \left (a+b \sqrt [3]{c+d x}\right )} \left (-40320 i \left (-1+e^{2 i \left (a+b \sqrt [3]{c+d x}\right )}\right )-40320 b \left (1+e^{2 i \left (a+b \sqrt [3]{c+d x}\right )}\right ) \sqrt [3]{c+d x}+20160 i b^2 \left (-1+e^{2 i \left (a+b \sqrt [3]{c+d x}\right )}\right ) (c+d x)^{2/3}-i b^8 d^2 \left (-1+e^{2 i \left (a+b \sqrt [3]{c+d x}\right )}\right ) x^2 (c+d x)^{2/3}+2 b^7 d \left (1+e^{2 i \left (a+b \sqrt [3]{c+d x}\right )}\right ) x \sqrt [3]{c+d x} (3 c+4 d x)-240 i b^4 \left (-1+e^{2 i \left (a+b \sqrt [3]{c+d x}\right )}\right ) \sqrt [3]{c+d x} (6 c+7 d x)-24 b^5 \left (1+e^{2 i \left (a+b \sqrt [3]{c+d x}\right )}\right ) (c+d x)^{2/3} (9 c+14 d x)+240 b^3 \left (1+e^{2 i \left (a+b \sqrt [3]{c+d x}\right )}\right ) (27 c+28 d x)+2 i b^6 \left (-1+e^{2 i \left (a+b \sqrt [3]{c+d x}\right )}\right ) \left (9 c^2+36 c d x+28 d^2 x^2\right )\right )}{2 b^9 d^3} \]
(3*((-40320*I)*(-1 + E^((2*I)*(a + b*(c + d*x)^(1/3)))) - 40320*b*(1 + E^( (2*I)*(a + b*(c + d*x)^(1/3))))*(c + d*x)^(1/3) + (20160*I)*b^2*(-1 + E^(( 2*I)*(a + b*(c + d*x)^(1/3))))*(c + d*x)^(2/3) - I*b^8*d^2*(-1 + E^((2*I)* (a + b*(c + d*x)^(1/3))))*x^2*(c + d*x)^(2/3) + 2*b^7*d*(1 + E^((2*I)*(a + b*(c + d*x)^(1/3))))*x*(c + d*x)^(1/3)*(3*c + 4*d*x) - (240*I)*b^4*(-1 + E^((2*I)*(a + b*(c + d*x)^(1/3))))*(c + d*x)^(1/3)*(6*c + 7*d*x) - 24*b^5* (1 + E^((2*I)*(a + b*(c + d*x)^(1/3))))*(c + d*x)^(2/3)*(9*c + 14*d*x) + 2 40*b^3*(1 + E^((2*I)*(a + b*(c + d*x)^(1/3))))*(27*c + 28*d*x) + (2*I)*b^6 *(-1 + E^((2*I)*(a + b*(c + d*x)^(1/3))))*(9*c^2 + 36*c*d*x + 28*d^2*x^2)) )/(2*b^9*d^3*E^(I*(a + b*(c + d*x)^(1/3))))
Time = 0.66 (sec) , antiderivative size = 540, normalized size of antiderivative = 1.01, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {3913, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x^2 \cos \left (a+b \sqrt [3]{c+d x}\right ) \, dx\) |
\(\Big \downarrow \) 3913 |
\(\displaystyle \frac {3 \int \left (\frac {\cos \left (a+b \sqrt [3]{c+d x}\right ) (c+d x)^{8/3}}{d^2}-\frac {2 c \cos \left (a+b \sqrt [3]{c+d x}\right ) (c+d x)^{5/3}}{d^2}+\frac {c^2 \cos \left (a+b \sqrt [3]{c+d x}\right ) (c+d x)^{2/3}}{d^2}\right )d\sqrt [3]{c+d x}}{d}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {3 \left (\frac {40320 \sin \left (a+b \sqrt [3]{c+d x}\right )}{b^9 d^2}-\frac {40320 \sqrt [3]{c+d x} \cos \left (a+b \sqrt [3]{c+d x}\right )}{b^8 d^2}-\frac {20160 (c+d x)^{2/3} \sin \left (a+b \sqrt [3]{c+d x}\right )}{b^7 d^2}+\frac {6720 (c+d x) \cos \left (a+b \sqrt [3]{c+d x}\right )}{b^6 d^2}-\frac {240 c \cos \left (a+b \sqrt [3]{c+d x}\right )}{b^6 d^2}+\frac {1680 (c+d x)^{4/3} \sin \left (a+b \sqrt [3]{c+d x}\right )}{b^5 d^2}-\frac {240 c \sqrt [3]{c+d x} \sin \left (a+b \sqrt [3]{c+d x}\right )}{b^5 d^2}-\frac {336 (c+d x)^{5/3} \cos \left (a+b \sqrt [3]{c+d x}\right )}{b^4 d^2}+\frac {120 c (c+d x)^{2/3} \cos \left (a+b \sqrt [3]{c+d x}\right )}{b^4 d^2}-\frac {2 c^2 \sin \left (a+b \sqrt [3]{c+d x}\right )}{b^3 d^2}-\frac {56 (c+d x)^2 \sin \left (a+b \sqrt [3]{c+d x}\right )}{b^3 d^2}+\frac {40 c (c+d x) \sin \left (a+b \sqrt [3]{c+d x}\right )}{b^3 d^2}+\frac {2 c^2 \sqrt [3]{c+d x} \cos \left (a+b \sqrt [3]{c+d x}\right )}{b^2 d^2}+\frac {8 (c+d x)^{7/3} \cos \left (a+b \sqrt [3]{c+d x}\right )}{b^2 d^2}-\frac {10 c (c+d x)^{4/3} \cos \left (a+b \sqrt [3]{c+d x}\right )}{b^2 d^2}+\frac {c^2 (c+d x)^{2/3} \sin \left (a+b \sqrt [3]{c+d x}\right )}{b d^2}+\frac {(c+d x)^{8/3} \sin \left (a+b \sqrt [3]{c+d x}\right )}{b d^2}-\frac {2 c (c+d x)^{5/3} \sin \left (a+b \sqrt [3]{c+d x}\right )}{b d^2}\right )}{d}\) |
(3*((-240*c*Cos[a + b*(c + d*x)^(1/3)])/(b^6*d^2) - (40320*(c + d*x)^(1/3) *Cos[a + b*(c + d*x)^(1/3)])/(b^8*d^2) + (2*c^2*(c + d*x)^(1/3)*Cos[a + b* (c + d*x)^(1/3)])/(b^2*d^2) + (120*c*(c + d*x)^(2/3)*Cos[a + b*(c + d*x)^( 1/3)])/(b^4*d^2) + (6720*(c + d*x)*Cos[a + b*(c + d*x)^(1/3)])/(b^6*d^2) - (10*c*(c + d*x)^(4/3)*Cos[a + b*(c + d*x)^(1/3)])/(b^2*d^2) - (336*(c + d *x)^(5/3)*Cos[a + b*(c + d*x)^(1/3)])/(b^4*d^2) + (8*(c + d*x)^(7/3)*Cos[a + b*(c + d*x)^(1/3)])/(b^2*d^2) + (40320*Sin[a + b*(c + d*x)^(1/3)])/(b^9 *d^2) - (2*c^2*Sin[a + b*(c + d*x)^(1/3)])/(b^3*d^2) - (240*c*(c + d*x)^(1 /3)*Sin[a + b*(c + d*x)^(1/3)])/(b^5*d^2) - (20160*(c + d*x)^(2/3)*Sin[a + b*(c + d*x)^(1/3)])/(b^7*d^2) + (c^2*(c + d*x)^(2/3)*Sin[a + b*(c + d*x)^ (1/3)])/(b*d^2) + (40*c*(c + d*x)*Sin[a + b*(c + d*x)^(1/3)])/(b^3*d^2) + (1680*(c + d*x)^(4/3)*Sin[a + b*(c + d*x)^(1/3)])/(b^5*d^2) - (2*c*(c + d* x)^(5/3)*Sin[a + b*(c + d*x)^(1/3)])/(b*d^2) - (56*(c + d*x)^2*Sin[a + b*( c + d*x)^(1/3)])/(b^3*d^2) + ((c + d*x)^(8/3)*Sin[a + b*(c + d*x)^(1/3)])/ (b*d^2)))/d
3.1.95.3.1 Defintions of rubi rules used
Int[((a_.) + Cos[(c_.) + (d_.)*((e_.) + (f_.)*(x_))^(n_)]*(b_.))^(p_.)*((g_ .) + (h_.)*(x_))^(m_.), x_Symbol] :> Simp[1/(n*f) Subst[Int[ExpandIntegra nd[(a + b*Cos[c + d*x])^p, x^(1/n - 1)*(g - e*(h/f) + h*(x^(1/n)/f))^m, x], x], x, (e + f*x)^n], x] /; FreeQ[{a, b, c, d, e, f, g, h, m}, x] && IGtQ[p , 0] && IntegerQ[1/n]
Leaf count of result is larger than twice the leaf count of optimal. \(1808\) vs. \(2(477)=954\).
Time = 1.62 (sec) , antiderivative size = 1809, normalized size of antiderivative = 3.37
method | result | size |
derivativedivides | \(\text {Expression too large to display}\) | \(1809\) |
default | \(\text {Expression too large to display}\) | \(1809\) |
parts | \(\text {Expression too large to display}\) | \(2944\) |
3/d^3/b^3*(a^2*c^2*sin(a+b*(d*x+c)^(1/3))-2*a*c^2*(cos(a+b*(d*x+c)^(1/3))+ (a+b*(d*x+c)^(1/3))*sin(a+b*(d*x+c)^(1/3)))+c^2*((a+b*(d*x+c)^(1/3))^2*sin (a+b*(d*x+c)^(1/3))-2*sin(a+b*(d*x+c)^(1/3))+2*(a+b*(d*x+c)^(1/3))*cos(a+b *(d*x+c)^(1/3)))+2/b^3*a^5*c*sin(a+b*(d*x+c)^(1/3))-10/b^3*a^4*c*(cos(a+b* (d*x+c)^(1/3))+(a+b*(d*x+c)^(1/3))*sin(a+b*(d*x+c)^(1/3)))+20/b^3*a^3*c*(( a+b*(d*x+c)^(1/3))^2*sin(a+b*(d*x+c)^(1/3))-2*sin(a+b*(d*x+c)^(1/3))+2*(a+ b*(d*x+c)^(1/3))*cos(a+b*(d*x+c)^(1/3)))-20/b^3*a^2*c*((a+b*(d*x+c)^(1/3)) ^3*sin(a+b*(d*x+c)^(1/3))+3*(a+b*(d*x+c)^(1/3))^2*cos(a+b*(d*x+c)^(1/3))-6 *cos(a+b*(d*x+c)^(1/3))-6*(a+b*(d*x+c)^(1/3))*sin(a+b*(d*x+c)^(1/3)))+10/b ^3*a*c*((a+b*(d*x+c)^(1/3))^4*sin(a+b*(d*x+c)^(1/3))+4*(a+b*(d*x+c)^(1/3)) ^3*cos(a+b*(d*x+c)^(1/3))-12*(a+b*(d*x+c)^(1/3))^2*sin(a+b*(d*x+c)^(1/3))+ 24*sin(a+b*(d*x+c)^(1/3))-24*(a+b*(d*x+c)^(1/3))*cos(a+b*(d*x+c)^(1/3)))-2 /b^3*c*((a+b*(d*x+c)^(1/3))^5*sin(a+b*(d*x+c)^(1/3))+5*(a+b*(d*x+c)^(1/3)) ^4*cos(a+b*(d*x+c)^(1/3))-20*(a+b*(d*x+c)^(1/3))^3*sin(a+b*(d*x+c)^(1/3))- 60*(a+b*(d*x+c)^(1/3))^2*cos(a+b*(d*x+c)^(1/3))+120*cos(a+b*(d*x+c)^(1/3)) +120*(a+b*(d*x+c)^(1/3))*sin(a+b*(d*x+c)^(1/3)))+1/b^6*a^8*sin(a+b*(d*x+c) ^(1/3))-8/b^6*a^7*(cos(a+b*(d*x+c)^(1/3))+(a+b*(d*x+c)^(1/3))*sin(a+b*(d*x +c)^(1/3)))+28/b^6*a^6*((a+b*(d*x+c)^(1/3))^2*sin(a+b*(d*x+c)^(1/3))-2*sin (a+b*(d*x+c)^(1/3))+2*(a+b*(d*x+c)^(1/3))*cos(a+b*(d*x+c)^(1/3)))-56/b^6*a ^5*((a+b*(d*x+c)^(1/3))^3*sin(a+b*(d*x+c)^(1/3))+3*(a+b*(d*x+c)^(1/3))^...
Time = 0.25 (sec) , antiderivative size = 182, normalized size of antiderivative = 0.34 \[ \int x^2 \cos \left (a+b \sqrt [3]{c+d x}\right ) \, dx=\frac {3 \, {\left (2 \, {\left (3360 \, b^{3} d x + 3240 \, b^{3} c - 12 \, {\left (14 \, b^{5} d x + 9 \, b^{5} c\right )} {\left (d x + c\right )}^{\frac {2}{3}} + {\left (4 \, b^{7} d^{2} x^{2} + 3 \, b^{7} c d x - 20160 \, b\right )} {\left (d x + c\right )}^{\frac {1}{3}}\right )} \cos \left ({\left (d x + c\right )}^{\frac {1}{3}} b + a\right ) - {\left (56 \, b^{6} d^{2} x^{2} + 72 \, b^{6} c d x + 18 \, b^{6} c^{2} - {\left (b^{8} d^{2} x^{2} - 20160 \, b^{2}\right )} {\left (d x + c\right )}^{\frac {2}{3}} - 240 \, {\left (7 \, b^{4} d x + 6 \, b^{4} c\right )} {\left (d x + c\right )}^{\frac {1}{3}} - 40320\right )} \sin \left ({\left (d x + c\right )}^{\frac {1}{3}} b + a\right )\right )}}{b^{9} d^{3}} \]
3*(2*(3360*b^3*d*x + 3240*b^3*c - 12*(14*b^5*d*x + 9*b^5*c)*(d*x + c)^(2/3 ) + (4*b^7*d^2*x^2 + 3*b^7*c*d*x - 20160*b)*(d*x + c)^(1/3))*cos((d*x + c) ^(1/3)*b + a) - (56*b^6*d^2*x^2 + 72*b^6*c*d*x + 18*b^6*c^2 - (b^8*d^2*x^2 - 20160*b^2)*(d*x + c)^(2/3) - 240*(7*b^4*d*x + 6*b^4*c)*(d*x + c)^(1/3) - 40320)*sin((d*x + c)^(1/3)*b + a))/(b^9*d^3)
\[ \int x^2 \cos \left (a+b \sqrt [3]{c+d x}\right ) \, dx=\int x^{2} \cos {\left (a + b \sqrt [3]{c + d x} \right )}\, dx \]
Leaf count of result is larger than twice the leaf count of optimal. 1349 vs. \(2 (477) = 954\).
Time = 0.40 (sec) , antiderivative size = 1349, normalized size of antiderivative = 2.51 \[ \int x^2 \cos \left (a+b \sqrt [3]{c+d x}\right ) \, dx=\text {Too large to display} \]
3*(a^2*c^2*sin((d*x + c)^(1/3)*b + a) - 2*(((d*x + c)^(1/3)*b + a)*sin((d* x + c)^(1/3)*b + a) + cos((d*x + c)^(1/3)*b + a))*a*c^2 + 2*a^5*c*sin((d*x + c)^(1/3)*b + a)/b^3 - 10*(((d*x + c)^(1/3)*b + a)*sin((d*x + c)^(1/3)*b + a) + cos((d*x + c)^(1/3)*b + a))*a^4*c/b^3 + (2*((d*x + c)^(1/3)*b + a) *cos((d*x + c)^(1/3)*b + a) + (((d*x + c)^(1/3)*b + a)^2 - 2)*sin((d*x + c )^(1/3)*b + a))*c^2 + a^8*sin((d*x + c)^(1/3)*b + a)/b^6 - 8*(((d*x + c)^( 1/3)*b + a)*sin((d*x + c)^(1/3)*b + a) + cos((d*x + c)^(1/3)*b + a))*a^7/b ^6 + 20*(2*((d*x + c)^(1/3)*b + a)*cos((d*x + c)^(1/3)*b + a) + (((d*x + c )^(1/3)*b + a)^2 - 2)*sin((d*x + c)^(1/3)*b + a))*a^3*c/b^3 + 28*(2*((d*x + c)^(1/3)*b + a)*cos((d*x + c)^(1/3)*b + a) + (((d*x + c)^(1/3)*b + a)^2 - 2)*sin((d*x + c)^(1/3)*b + a))*a^6/b^6 - 20*(3*(((d*x + c)^(1/3)*b + a)^ 2 - 2)*cos((d*x + c)^(1/3)*b + a) + (((d*x + c)^(1/3)*b + a)^3 - 6*(d*x + c)^(1/3)*b - 6*a)*sin((d*x + c)^(1/3)*b + a))*a^2*c/b^3 - 56*(3*(((d*x + c )^(1/3)*b + a)^2 - 2)*cos((d*x + c)^(1/3)*b + a) + (((d*x + c)^(1/3)*b + a )^3 - 6*(d*x + c)^(1/3)*b - 6*a)*sin((d*x + c)^(1/3)*b + a))*a^5/b^6 + 10* (4*(((d*x + c)^(1/3)*b + a)^3 - 6*(d*x + c)^(1/3)*b - 6*a)*cos((d*x + c)^( 1/3)*b + a) + (((d*x + c)^(1/3)*b + a)^4 - 12*((d*x + c)^(1/3)*b + a)^2 + 24)*sin((d*x + c)^(1/3)*b + a))*a*c/b^3 + 70*(4*(((d*x + c)^(1/3)*b + a)^3 - 6*(d*x + c)^(1/3)*b - 6*a)*cos((d*x + c)^(1/3)*b + a) + (((d*x + c)^(1/ 3)*b + a)^4 - 12*((d*x + c)^(1/3)*b + a)^2 + 24)*sin((d*x + c)^(1/3)*b ...
Leaf count of result is larger than twice the leaf count of optimal. 1104 vs. \(2 (477) = 954\).
Time = 0.28 (sec) , antiderivative size = 1104, normalized size of antiderivative = 2.06 \[ \int x^2 \cos \left (a+b \sqrt [3]{c+d x}\right ) \, dx=\text {Too large to display} \]
3*(2*(((d*x + c)^(1/3)*b + a)*b^6*c^2 - a*b^6*c^2 - 5*((d*x + c)^(1/3)*b + a)^4*b^3*c + 20*((d*x + c)^(1/3)*b + a)^3*a*b^3*c - 30*((d*x + c)^(1/3)*b + a)^2*a^2*b^3*c + 20*((d*x + c)^(1/3)*b + a)*a^3*b^3*c - 5*a^4*b^3*c + 4 *((d*x + c)^(1/3)*b + a)^7 - 28*((d*x + c)^(1/3)*b + a)^6*a + 84*((d*x + c )^(1/3)*b + a)^5*a^2 - 140*((d*x + c)^(1/3)*b + a)^4*a^3 + 140*((d*x + c)^ (1/3)*b + a)^3*a^4 - 84*((d*x + c)^(1/3)*b + a)^2*a^5 + 28*((d*x + c)^(1/3 )*b + a)*a^6 - 4*a^7 + 60*((d*x + c)^(1/3)*b + a)^2*b^3*c - 120*((d*x + c) ^(1/3)*b + a)*a*b^3*c + 60*a^2*b^3*c - 168*((d*x + c)^(1/3)*b + a)^5 + 840 *((d*x + c)^(1/3)*b + a)^4*a - 1680*((d*x + c)^(1/3)*b + a)^3*a^2 + 1680*( (d*x + c)^(1/3)*b + a)^2*a^3 - 840*((d*x + c)^(1/3)*b + a)*a^4 + 168*a^5 - 120*b^3*c + 3360*((d*x + c)^(1/3)*b + a)^3 - 10080*((d*x + c)^(1/3)*b + a )^2*a + 10080*((d*x + c)^(1/3)*b + a)*a^2 - 3360*a^3 - 20160*(d*x + c)^(1/ 3)*b)*cos((d*x + c)^(1/3)*b + a)/(b^8*d^2) + (((d*x + c)^(1/3)*b + a)^2*b^ 6*c^2 - 2*((d*x + c)^(1/3)*b + a)*a*b^6*c^2 + a^2*b^6*c^2 - 2*((d*x + c)^( 1/3)*b + a)^5*b^3*c + 10*((d*x + c)^(1/3)*b + a)^4*a*b^3*c - 20*((d*x + c) ^(1/3)*b + a)^3*a^2*b^3*c + 20*((d*x + c)^(1/3)*b + a)^2*a^3*b^3*c - 10*(( d*x + c)^(1/3)*b + a)*a^4*b^3*c + 2*a^5*b^3*c + ((d*x + c)^(1/3)*b + a)^8 - 8*((d*x + c)^(1/3)*b + a)^7*a + 28*((d*x + c)^(1/3)*b + a)^6*a^2 - 56*(( d*x + c)^(1/3)*b + a)^5*a^3 + 70*((d*x + c)^(1/3)*b + a)^4*a^4 - 56*((d*x + c)^(1/3)*b + a)^3*a^5 + 28*((d*x + c)^(1/3)*b + a)^2*a^6 - 8*((d*x + ...
Timed out. \[ \int x^2 \cos \left (a+b \sqrt [3]{c+d x}\right ) \, dx=\int x^2\,\cos \left (a+b\,{\left (c+d\,x\right )}^{1/3}\right ) \,d x \]